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Trick or Treat by °chanelqueen17 1 month 2 weeks ago

^nat

After months of work, chanelqueen17 has created a gorgeous scene of Alice and Oz from Pandora Hearts, using scans that didn't even feature both characters together. Even after spending so much time on matching the details of the characters to their new looks, chanelqueen17 didn't stop there and went all out on the background too! This wallpaper definitely needs to be seen!

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ShoutBox

~Loleta 1 minute ago

Hey there kitty.

~kittylove 10 minutes ago

Hello everyone

☆Bantam 12 minutes ago

Hello, is it me you're looking for?

$authemis 23 minutes ago

Hello

$rabbitking 27 minutes ago

So it's the body that makes the difference? wtf happen

~Loleta 27 minutes ago

I wouldn't find that creepy myself.

*moutonzare 29 minutes ago

Mostly because you would be girl.

$rabbitking 32 minutes ago

I just thought of something interesting that i'd like to share. If you put my brain inside the head of a 14 year old girl, i wouldnt be creepy

*moutonzare 36 minutes ago

Rabbit

$rabbitking 40 minutes ago

Retard

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Jack's Comments

11 Pages: [ 1 ] 2 3 4 5 Last »

Drawing Questions

2 years 1 month ago

"Probably the best book on drawing is The New Drawing on the Right Side of the Brain. It doesn't replace practice, but the methods Betty Edwards teaches will give you a kick start and prevent you from getting frustrated at the beginning. I drew the following after just a few hours of reading:

I know it's far from being perfect, however considering I wasn't even able to draw stick-figures before reading the book it isn't bad at all. "
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Does Heaven and Hell exist?

2 years 3 months ago

"

Kaze-no-Mikiri
Just because you can't see something, then catch it and hold it in your hand doesn't mean it isn't there, right? Take the wind for example...

But unlike all the other holy humbug you can
* feel the pressure the wind exerts on your skin
* you can build devices to measure it
* you can freeze the air so it becomes liquid
* you can make it visible by adding smoke (e.g. wind tunnel)
* ...

do something like this with heaven and hell and i'll gladly believe it. However not being able to disprove something is no proof by itself. Take the following as an example: Right beside me there's floating a mysterious creature with pink fur and orange horns. It is invisible to everyone but me, nor does it interact with it's environment in any way. Now this must be true since you can't disprove it.

If one states something to be true out of nowhere he is the one with the burden of proof, not the rest of humanity.

Triste
Apologies to anyone who might be offended by this remark.

Don't apologize to others just because they prefer to be delusional about god, heaven and hell, or do you apologize to someone running his head against a wall for offending him because you are not doing the same."
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Hi im new

2 years 4 months ago

"Hi TrisoX,

welcome to AP :), however this is the wrong subforum for your introduction. Please post it in the Introductions Forum. As for your question you'll find the answer here."
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Power over your dreams

2 years 4 months ago

"I had one lucid dream during a polyphasic sleep experiment* I did a few month ago. It was very short though (about two minutes), but nevertheless an amazing experience. I was fully aware I was dreaming and to some extent I was able to manipulate my surroundings. Unfortunately before I could do more than some exploring the dream ended. I'm planning to repeat that experiment in a few weeks from now with better preparation (and hopefully better results). What I know from others however is that you aren't completely godlike, for example your dreams still have some physic rules you need to obey to (not neccessarily the rules of the real world, so flying, telekinesis and such are possible), furthermore those skills can be trained and you get better with every dream.

*)Polyphasic sleep is a special form of sleep where you take your sleep in several short naps over the day instead of one big chunk. A very popular form and likely the most extreme is known as uberman or davinci sleep (Kramer form Seinfeld did it in the episode 'The Friars Club'). In this schedule your total sleeping time is reduced to about 1.5-3 hours a day, split into 6 equally long and equally spaced naps over the day. In addition polyphasic sleepers often report more intense dreams and an increased frequency of lucid dreams."
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Yeah so i purchased Windows for the First time....

2 years 8 months ago

"Why didn't you make a copy of your important data before formatting? If Windows refuses to start, to copy your data you could always use some cd-bootable linux.
"
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The Green Room Riddle

2 years 8 months ago

"There are beginners but no advanced learners,
there are commanders but no subordinates,
there are winners but no losers,
..."
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Logical Problems II

2 years 8 months ago

"I just tried to show what to do without actually doing it. I try to put it differently: Print these figures and cut out the first one. Then try to make two straight cuts so that the resulting pieces can be assembled to perfectly fit the second figure.
"
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Logical Problems II

2 years 8 months ago

"

RobinPerris

The father comes to the son and tells him, "I have here 10 $10 and 10 $100. Arrange this money in any amount and put them into these 2 hats, anyway you want. I'll mix the hats, but not changing the money from one hat to an other. Then you'll remove one bill from any of the hats and if you get a $100 bill, it's yours but if you get a 10 dollars bill you wash my car." Which is the best way to arrange these bills to get the max chance of getting this $100?

I'll give it a try:

SPOILER (click to view)
Put one $100 bill in hat one and the rest in hat two. Your chance to pick hat one is 50% which will be a sure win, however if you happen to pick hat two the probability for a win will be 9/19. Together you get 9/19 * 1/2 + 1 * 1/2 = 14/19 which is about 74%.
"
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Logical Problems II

2 years 8 months ago

"

FirestormII

SPOILER (click to view)
But if i make two striaght cuts passing or staying on the center in both, horizontal and vertical ways. I would get resulting 4 parts which could be put together to form a square. You know, like a cross sign thingy. Or a crosshair or something.

Do you mean like this?

I don't see how this could be put together to form a square."
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Logical Problems II

2 years 8 months ago

"Imagine the object to be a piece of paper now take a pair of scissors and make two straight cuts. Now rearrange the parts so that they form a square. Here's an example with two arbitrary cutting lines which result in a pretty arbitrary square:

"
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Logical Problems II

2 years 8 months ago

"Here's the solution to your riddle Deoxys114:

SPOILER (click to view)

You used a ceasar with an offset of one, so
"Dpohsbuvmbujpot. Zpv gjhvsfe ju pvu." becomes "Congratulations. You figured it out.". By the way try the same with "HAL" from 2001: A Space Odyssey.

galapia you have an mistake in your second equation it should be:

SPOILER (click to view)

x + 25 = y
y + 7 = (x + 7) * 5
x + 25 + 7 = (x + 7) * 5
x + 32 = 5x + 35
-4x = 3
x = -3/4

"
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Logical Problems II

2 years 8 months ago

"Yes you're correct. Here's a graphical version of the solution:

SPOILER (click to view)

The gradient of the red and blue triangle aren't the same, thus the whole figure isn't a triangle. Like Kyto said if you draw a straight line from the left to the top corner the figure is underneath it. The area between line and figure is exactly 0.5, the same is true for the second figure, but here the figure is above the line. The area is again 0.5. Together this is exactly the area of the hole.

Here's the next one:

Place two straight cuts through the above object in such a way that the resulting parts can be put together to form a square. Note: The small squares are just there to form subsidiary lines, your cuts don't need to follow them."
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Logical Problems II

2 years 8 months ago

"

Deoxys114

SPOILER (click to view)
The yellow block is no longer on top of the green block, rather it is pushed over one space. Thus it makes the hole.

In some way your solution hits the bull's-eye, however it doesn't explain why two similar looking triangles, consisting of identical parts, seem to have different areas.

Peterue

WOw, pretty difficult riddles here. Hmm quite a very interesting topic. Thanks for sharing all the riddles, it was fun trying to solve them.

You're welcome! Feel free to share some of yours."
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Logical Problems II

2 years 8 months ago

"Ok, first the solution to the game show riddle:

SPOILER (click to view)

Initially the probability to pick the right door is 1/3. This means that the probability for the price to be behind the other two doors is 2/3 (1/3 for each door). Now the host opens one of the other doors and reveals the goat, this doesn't change the combined probability, however it changes the probabilities for each single door. The open door has now a probability of 0 to hide the car, but this means the other of the two doors has now the probability of 2/3 to hide the car. Hence if you switch your chances to win are doubled.
An other way to approach this is to imagine a game with 1000 doors instead of three. We have a chance of 1/1000 to pick the right door at the beginning, but after the host opens 998 doors revealing only goats, leaving only one other door for the car to hide it is pretty obvious what to do.
Here's a little example. Lets say the car is behind door 1. If you stick with your first choice you'll win in one out of three cases. If you choose to switch there are the following possibilities:

first choice | door opened | last choice | win
1 | 2/3 | 3/2 | no
2 | 3 | 1 | yes
3 | 2 | 1 | yes

Altogether you win in two out of three cases.

I don't have much on your goat riddle by now. The only solution I can currently imagine is the following:

SPOILER (click to view)

One of the goats is pregnant, meaning that this goat is worth two goats totaling an amount of 20 goats. Now the splitting is easily done: Son number one gets 9 goats including the pregnant one, son number two gets 5 goats and son number three gets 4 goats.

Here's the next problem:

All parts in both figures are exactly the same, but then where comes the hole from?

"
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Logical Problems II

2 years 8 months ago

"Yes I already knew a similar problem, so it was not too hard for me. I'll give you the answer for the gameshow riddle now, but I won't tell yet why it's correct:

SPOILER (click to view)
The answer is that you should always switch.

Try to find the answer to that question for yourself."
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Logical Problems II

2 years 9 months ago

"I'm sorry but both of you are wrong. There's a perfectly logical reasoning behind this which will lead to a definite answer."
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Logical Problems II

2 years 9 months ago

"

DaPlatypus
I'm going to go ahead and retry the 6 coin riddle (as I've still got nothing on the scale riddle):

SPOILER (click to view)

1. Take the coin on the bottom right and move it so that it is touching the 2 coins on the original bottom row.
2. Take the coin that was initially directly to the left of the coin moved in step 1 and move it right so that it is touching the 2 coins on the middle and right of the top row.
3. Move the coin on the top right so that it looks like the picture serving as the goal. (This will make it touch the coins moved in step 1 and 2)

I am much more confident with this answer than my previous one so I hope it doesn't break any of the rules XP.

Yes that's the solution!

Here's one of my all time favourites to kill time while venting your head from the scale riddle:

One of three doors hides a car (all three equally likely) and the other two hide goats. You choose Door 1. The host, who knows where the car is, then opens one of the other two doors to reveal a goat, and asks whether you wish to switch your choice. Say he opens Door 3; should you stick with your original choice, Door 1, or switch to Door 2?
"
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Logical Problems II

2 years 9 months ago

"

DaPlatypus

I'm not sure about the other coin riddle, but my guess for the answer would be:

SPOILER (click to view)
1. Take the coin on the very right of the top row and move it down so that it is touching the middle coin and the right coin of the initial bottom row.
2. Take the coin on the left of the now middle row and move it down so that it is touching the coin that was previously, directly to its right and the coin that you moved in step 1.
3. Move the middle coin of the middle row to the left to take the place of the coin you moved in step 2, so that it is touching the coin moved in step 2 and the coin above it.

I actually had some trouble understanding what this riddle was asking and for a while I thought I had found an answer that only required two moves (but this seemed too easy so I changed it).

SPOILER (click to view)
Your third step isn't according to the rules because you would move the upper left coin and the lower left coin out of their positions.

"
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Logical Problems II

2 years 9 months ago

"

DaPlatypus

Solution for ten coins (assuming we have 5 moves now instead of 4):

SPOILER (click to view)
1. Take the coin 4th from the left and move it onto the coin on the very left.
You now have 8 coins to the right of this pile which you solve with the same steps as before
2. Take the coin 5th from the left and move it onto the coin 2nd from the left.
3. Take the coin directly on the right of this pile and move it 2 coins to the right.
4 & 5. From here you have one coin on each side of two piles of 2 coins so you just move either the left or the right coin onto the matching one and you're done.

Ok you're too good :P, here's a tough nut to crack for you:

You are given 12 identical-looking coins, one of which is counterfeit and weighs slightly more or less (you don't know which!) than the others. You are given a balance scale which lets you put the same number of coins on each side and observe which side (if either) is heavier. How can you identify the counterfeit and tell whether it is heavy or light, in 3 weighings?
"
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Logical Problems II

2 years 9 months ago

"

DaPlatypus

Okay I have an answer to the coin problem:

SPOILER (click to view)

1. Take the coin 5th from the left and move it onto the coin 2nd from the left.
2. Take the coin directly on the right of this pile and move it 2 coins to the right.
3 & 4. From here you have one coin on each side of two piles of 2 coins so you just move either the left or the right coin onto the matching one and you're done.

Exactly, now give it a try with 10 coins.

Another nice riddle with coins is the following:
Given the arrangement of coins on the left the goal is to reach the formation on the right in only three moves. This arrangemnt has room for a 7th coin in the middle with all outer coins touching it. A coin may only be placed on a new position if it touches two other coins. All moves must be done within the plane of the initial arrangement. The positions of the other coins must not be changed during this process.
"
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Logical Problems II

2 years 9 months ago

"

XeroMancer

SPOILER (click to view)
I get the feeling that there is no answer to this one unless we get to move the coins over the other side of the coin-line.That way it goes like this:we place the first one on the fourth,the third one on the sixth,the last one on the fifth and then we move the second one through the other side of the screen to go on the seventh

That's not a valid solution since you move for example the third coin over three coins. The only valid moves are shown below (the inverse moves of course are valid too):

XeroMancer if it's an acurate scale showing grams I got a solution:

SPOILER (click to view)

Put one coin of bag one, two coins of bag two, ... and ten coins of bag ten on the scale. In total there are now 55 coins. The total weight should be 55*400g = 22kg. But it's less since one bag contained false coins. Let's say it was bag 4, since we put 4 coins from bag 4 on the scale we get 4 grams less than we expect. So the number of missing grams indicates the bag with the false coins.

"
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Logical Problems II

2 years 9 months ago

"For the curious, here's the solution:

SPOILER (click to view)

From the first two sentences we get a linear equation system.
Silvia is exactly 25 years younger than her mother. =>
S + 25 = M (1)
In 7 years the mother will be 5 times as old as Silvia. =>
M + 7 = (S + 7) * 5 (2)
Inserting equation (1) in equation (2) we get:
S + 25 + 7 = (S + 7) * 5
S + 32 = 5S + 35
-4S = 3
S = -3/4 years = -9 month

Where is Silvias father?
Since Silvia will be born in 9 month it's currently the moment of procreation. Therefore the father is on Silvias mother.

Here's a new one:

Given the following arrangement of 8 coins, your goal is to create 4 piles with 2 coins each.

With each move you must jump with the moved coin exactly over two coins, it is then placed on the next coin. You are allowed to make 4 moves."
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Logical Problems II

2 years 9 months ago

"I'm sorry guys, no typos and no forgotten parts of the riddle. It's solvable the way it is now.

Hint:

SPOILER (click to view)
If you know the age of Silvia you will also know where her father is.

PS: ExileZX the age you got isn't correct. 40 - 15 = 25, but in seven years Silvias age will be 22 then, meaning Silvias Mother would be 110."
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Jack's Comments

Drawing Questions

Does Heaven and Hell exist?

Hi im new

Power over your dreams

Yeah so i purchased Windows for the First time....

The Green Room Riddle

Logical Problems II

Logical Problems II

Logical Problems II

Logical Problems II

Logical Problems II

Logical Problems II

Logical Problems II

Logical Problems II

Logical Problems II

Logical Problems II

Logical Problems II

Logical Problems II

Logical Problems II

Logical Problems II

Logical Problems II

Logical Problems II

Logical Problems II